#include<stdio.h>
int Add(int a, int b)
{
return a + b;
}
int main()
{
int x = 1;
int y = 2;
int ret = Add(x, y);
printf("%p \n", Add);//打印函数名
printf("%p \n", &Add);//对函数名取地址
return 0;
}
#include <stdio.h>
int add(int a, int b)//加法
{
return a + b;
}
int sub(int a, int b)//减法
{
return a - b;
}
int mul(int a, int b)//乘法
{
return a * b;
}
int div(int a, int b)//除法
{
return a / b;
}
int main()
{
int x, y;
int input = 1;
int ret = 0;
do//简单计算机的模拟实现
{
printf(" 1:add 2:sub \n");
printf(" 3:mul 4:div \n");
printf(" 0:exit \n");
printf("请选择:");
scanf("%d", &input);
switch (input)
{
case 1:
printf("输入操作数:");
scanf("%d %d", &x, &y);
ret = add(x, y);
printf("ret = %d\n", ret);
break;
case 2:
printf("输入操作数:");
scanf("%d %d", &x, &y);
ret = sub(x, y);
printf("ret = %d\n", ret);
break;
case 3:
printf("输入操作数:");
scanf("%d %d", &x, &y);
ret = mul(x, y);
printf("ret = %d\n", ret);
break;
case 4:
printf("输入操作数:");
scanf("%d %d", &x, &y);
ret = div(x, y);
printf("ret = %d\n", ret);
break;
case 0:
printf("退出程序\n");
break;
default:
printf("选择错误\n");
break;
}
} while (input);
return 0;
}
通过观察我们发现代码有很多冗余的部分,我们可以通过下面两种方法简化
3.1 函数指针数组
类比指针数组,函数指针数组就是每个数组元素是个函数指针
#include <stdio.h>
int add(int a, int b)
{
return a + b;
}
int sub(int a, int b)
{
return a - b;
}
int mul(int a, int b)
{
return a * b;
}
int div(int a, int b)
{
return a / b;
}
int main()
{
int x, y;
int input = 1;
int ret = 0;
int(*p[5])(int x, int y) = { 0, add, sub, mul, div };
//0元素方便输入
//p先与[5]结合是个数组,每个元素是个函数指针
do
{
printf(" 1:add 2:sub \n");
printf(" 3:mul 4:div \n");
printf(" 0:exit \n");
printf("请选择:");
scanf("%d", &input);
if ((input <= 4 && input >= 1))
{
printf("输入操作数:");
scanf("%d %d", &x, &y);
ret = (*p[input])(x, y);
printf("ret = %d\n", ret);
}
else if (input == 0)
{
printf("退出计算器\n");
}
else
{
printf("输⼊有误\n");
}
} while (input);
return 0;
}
#include <stdio.h>
int add(int a, int b)
{
return a + b;
}
int sub(int a, int b)
{
return a - b;
}
int mul(int a, int b)
{
return a * b;
}
int div(int a, int b)
{
return a / b;
}
void calc(int(*pf)(int, int))
//用函数指针来接收函数地址
{
int ret = 0;
int x, y;
printf("输入操作数:");
scanf("%d %d", &x, &y);
ret = pf(x, y);
printf("ret = %d\n", ret);
}
int main()
{
int input = 1;
do
{
printf(" 1:add 2:sub \n");
printf(" 3:mul 4:div \n");
printf(" 0:exit \n");
printf("请选择:");
scanf("%d", &input);
switch (input)
{
case 1:
calc(add);//传入函数的地址
break;
case 2:
calc(sub);//传入函数的地址
break;
case 3:
calc(mul)//传入函数的地址
break;
case 4:
calc(div)//传入函数的地址
break;
case 0:
printf("退出程序\n");
break;
default:
printf("选择错误\n");
break;
}
} while (input);
return 0;
}